已知x+y=4,x^2+y^2=14,求xy的值
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已知x+y=4,x^2+y^2=14,求xy的值已知x+y=4,x^2+y^2=14,求xy的值已知x+y=4,x^2+y^2=14,求xy的值(x+y)^2=16而(x+y)^2=(x+y)(x+y
已知x+y=4,x^2+y^2=14,求xy的值
已知x+y=4,x^2+y^2=14,求xy的值
已知x+y=4,x^2+y^2=14,求xy的值
(x+y)^2 = 16
而(x+y)^2 = (x+y)(x+y) = x^2 + y^2 + 2xy = 14 + 2xy
所以 xy = (16 - 14)/2 = 1
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