((a+x)^m+1(b+x)^n-1)-(a+x)^m(b+x)^n4乘以x的4次乘以y的4次减二分之一xya^3+3a^2+3a+2x^2-2xy-8y^2-x-14y-63x^2+5xy-2y^2+x+9y-42x^2+y^2+3xy+4x+3y+2就以上几题!

来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/25 01:24:27
((a+x)^m+1(b+x)^n-1)-(a+x)^m(b+x)^n4乘以x的4次乘以y的4次减二分之一xya^3+3a^2+3a+2x^2-2xy-8y^2-x-14y-63x^2+5xy-2y^

((a+x)^m+1(b+x)^n-1)-(a+x)^m(b+x)^n4乘以x的4次乘以y的4次减二分之一xya^3+3a^2+3a+2x^2-2xy-8y^2-x-14y-63x^2+5xy-2y^2+x+9y-42x^2+y^2+3xy+4x+3y+2就以上几题!
((a+x)^m+1(b+x)^n-1)-(a+x)^m(b+x)^n
4乘以x的4次乘以y的4次减二分之一xy
a^3+3a^2+3a+2
x^2-2xy-8y^2-x-14y-6
3x^2+5xy-2y^2+x+9y-4
2x^2+y^2+3xy+4x+3y+2
就以上几题!

((a+x)^m+1(b+x)^n-1)-(a+x)^m(b+x)^n4乘以x的4次乘以y的4次减二分之一xya^3+3a^2+3a+2x^2-2xy-8y^2-x-14y-63x^2+5xy-2y^2+x+9y-42x^2+y^2+3xy+4x+3y+2就以上几题!
[(a+x)^m+1(b+x)^n-1]-(a+x)^m(b+x)^n
=(a+x)^m*(a+x)*(b+x)^(n-1)-(a+x)^m*(b+x)^(n-1)*(b+x) (这步利用同底数幂相乘,底数不变,指数相加)
= (a+x)^m*(b+x)^(n-1)[(a+x)-(b+x)](提取公因式)
=(a+x)^m*(b+x)^(n-1)*(a-b)
4乘以x的4次乘以y的4次减二分之一xy
=4x^4*y^4-xy/2
=xy/2(8x^3y^3-1)
=xy/2(2xy-1)(4x^2y^2+2xy+1)
a^3+3a^2+3a+2
=a^3+3a^2+2a+a+2
=a(a+2)(a+1)+a+2
=(a+2)(a^2+a+1)
x^2-2xy-8y^2-x-14y-6
=(x^2-2xy-8y^2)-x-14y-6
=(x-4y)(x+2y)-x-14y-6
=(x-4y-3)(x+2y+2)
3x^2+5xy-2y^2+x+9y-4
=(x+2y)(3x-y)+x+9y-4
=(x+2y)(3x-y)+(4x+8y-3x+y)-4
=(x+2y)(3x-y)+4(x+2y)-(3x-y)-4
=(x+2y)(3x-y) -(3x-y)+4(x+2y) -4
=(x+2y-1)(3x-y)+4(x+2y-1)
=(x+2y-1)(3x-y+4)
2x^2+y^2+3xy+4x+3y+2
=2x^2+y^2+2xy+xy+2x+2x+y+2y+2
=(2x^2+2xy+2x)+(xy+y^2+y)+(2x+2y+2)
=2x(x+y+1)+y(x+y+1)+2(x+y+1)
=(x+y+1)(2x+y+2)

((a+x)^m+1(b+x)^n-1)-(a+x)^m(b+x)^n
=(a+x)^m(b+x)n[(a+x)-(b+x)]
=(a+x)^m(b+x)n(a-b)
4x^4y^4-1/2*xy
=(1/2)xy(8x^3y^3-1)
=(1/2)xy(2xy-1)(4x^2y^2-2xy+1)
a^3+3a^2+3a+2
=(a^3-1)...

全部展开

((a+x)^m+1(b+x)^n-1)-(a+x)^m(b+x)^n
=(a+x)^m(b+x)n[(a+x)-(b+x)]
=(a+x)^m(b+x)n(a-b)
4x^4y^4-1/2*xy
=(1/2)xy(8x^3y^3-1)
=(1/2)xy(2xy-1)(4x^2y^2-2xy+1)
a^3+3a^2+3a+2
=(a^3-1)+3a^2+3a+3
=(a-1)(a^2+a+1)+3(a^2+a+1)
=(a-1+3)(a^2+a+1)
=(a+2)(a^2+a+1)
x^2-2xy-8y^2-x-14y-6
=(x-4y)(x+2y)-(3x+6y)+2x-8y-6
=(x-4y)(x+2y)-3(x+2y)+2x-8y-6
=(x+2y)(x-4y-3)+2(x-4y-3)
=(x-4y-3)(x+2y+2)
3x^2+5xy-2y^2+x+9y-4
=(3x-y)(x+2y)-(3x-y)+2x+8y-4
=(3x-y)(x+2y-1)+2(x+2y-1)
=(3x-y+2)(x+2y-1)
2x^2+y^2+3xy+4x+3y+2
=(2x+y)(x+y)+(2x+y)+2x+2y+2
=(2x+y)(x+y+1)+2(x+y+1)
=(2x+y+2)(x+y+1)

收起

z这年头积分真难赚啊!!
我上百度知道成瘾了!!!

4乘以x的4次乘以y的4次减二分之一xy
=4xy(x^3 y^3-1/8)
=4xy(xy-1/2)(x^2 y^2+1/2 xy+1/4)
a^3+3a^2+3a+2
=a^3+3a^2+3a+3-1
=(a-1)(a^2+a+1)+3(a^2+a+1)
=(a^2+a+1)(a-1+3)
=(a^2+a+1)(a+2)

(a+x)^(m+1)*(b+x)^(n-1)-(a+x)^m*(b+x)^n (a+x)^(m+1)(b+x)^(n-1) -(a+x)^m(b+x)^n各式的公因式是 分解因式(a+x)^(m+1)(b+x)^(n-1) -(a+x)^m(b+x)^n= 如果方程(M-N)X=M-N的解是X=1,那么( ) A.M=N B.M≠N C.M>N D.M 1,已知3m=4n,则m/m+n +n/m-n -m^2/m^2-n^2=2,若1除以[a-b/a-c除以(b-a/b-c除以x/c-b)]=-1,则x=3,若3x+4/(x-2)(x+3)=A/x-2 +B/x+3 则A= ,B= 计算(b-a)(b-a)^3(a- b)^5 x^m×(x^n)^3÷(x^m-1×2x^n-1) (2-6)^m+3×(b-a)^2×(a-b)^m×(b-a)^51.(b-a)(b-a)^3(a- b)^5 2 .x^m×(x^n)^3÷(x^m-1×2x^n-1) 3.(2-6)^m+3×(b-a)^2×(a-b)^m×(b-a)^5 定义在R上的函数f(x)=ln(x^2+1)+|x|,若f(m)>f(n),则m,n满足 A.m>n B.m 解方程求x a/(x-a)+b=1 (b≠1) m/x-n/(x+1)=0 (m≠n,mn≠0) (a+x)的M+1次方×(B+X)的N-1次方减去(a+x)的m次方×(b+x)的n次方分解因式 (a+x)的m+1次方*(b+x)的n-1次方-(a+x)的m次方*(b+x)的n次方 因式分解,(a+x)^m+1(b+x)^n-1-(a+x)^m(b+x)^n讲的详细一点,最好每一步都有解释, 分式加减法的计算题1:m-1/x + n-m/x2:1/m +3/m -5/m3:a²/a+b +b²+2ab/a+b4:x-2y/2x-y - x+y/2x-y5:m+2n/n-m + n/n-m -2n/n-m6:x²-5/x-2 - x/x-2 -1+x/2-x7:先化简,再求值.x²+1/x+1 - 2/x+1 .其中x=1/100 1,若A={2,3,4},B={x|x=n*m,m,n∈A,m≠n},则集合B中的元素个数是? *是一种特殊符号,满足a*b=1/(a+b),*是否满足(m*n)*x=m*(n*x),当m,n什么数时,� 已知集合A={x|x=3n+1,n∈Z},B={x|x=3n+2,n∈Z},M={x|x=6n+3,n∈Z}已知集合A={x|x=3n+1,n∈Z},B={x|x=3n+2,n∈Z},M={x|x=6n+3,n∈Z}1、若m∈M,是否有a∈A,b∈B,使m=a+b?2、对于任意a∈A,b∈B,是否一定有a+b=m且m∈ (1)-3a²b+6ab (2)(x²-2x)²+2(x²-2x)+1 (3)(m+n)(m-n)-(1-2n) (1)-3a^2b+6ab (2)(x^2-2x)^2+2(x^2-2x)+1 (3)(m+n)(m-n)-(1-2n) 6m(a-x)-8n(a-x) 3m(x-y)-n(y-x) (a-b)平方(a+b)-(b-a)平方 3x(x-1)立方-6xy(1-x)立方6m(a-x)-8n(a-x) 3m(x-y)-n(y-x)(a-b)平方(a+b)-(b-a)平方3x(x-1)立方-6xy(1-x)立方