如果a+b+c=0,1/a+1+1/b+2+1/c+3=0,那么（a+1)^2+(b+2)^2+(c+3)^2的值

如果a+b+c=0,1/a+1+1/b+2+1/c+3=0,那么（a+1)^2+(b+2)^2+(c+3)^2的值
如果a+b+c=0,1/a+1+1/b+2+1/c+3=0,那么（a+1)^2+(b+2)^2+(c+3)^2的值

如果a+b+c=0,1/a+1+1/b+2+1/c+3=0,那么（a+1)^2+(b+2)^2+(c+3)^2的值
设a+1=x,b+2=y,c+3=z .1/a+1+1/b+2+1/c+3=0所以1/x+1/y+1/z=0 所以yz+xz+xy=0.(a+1)^2+(b+2)^2+(c+2)^2=x^2+y^2+z^2 =x^2+y^2+z^2+2(xy+yz+zx) =(x+y+z)^2 =(a+1+b+2+c+3)^2 =(a+b+c+6)^2 =(0+6)^2 =36