根号x+y-1+(xy+2)∧2=0,则X,Y的取值

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根号x+y-1+(xy+2)∧2=0,则X,Y的取值根号x+y-1+(xy+2)∧2=0,则X,Y的取值根号x+y-1+(xy+2)∧2=0,则X,Y的取值根号x+y-1+(xy+2)∧2=0所以x+

根号x+y-1+(xy+2)∧2=0,则X,Y的取值
根号x+y-1+(xy+2)∧2=0,则X,Y的取值

根号x+y-1+(xy+2)∧2=0,则X,Y的取值
根号x+y-1+(xy+2)∧2=0
所以x+y-1=0
xy+2=0
所以y=1-x
代入
x-x²+2=0
x²-x-2=(x+1)(x-2)=0
x=-1,x=2
y=1-x
所以
x=-1,y=2
x=2,y=-1

xy+2=0 and x+y-1 故 x=-1,y=2或
x=2,y=-1