2x^2+3xy-2y^2+7y-y+3 因式分解
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2x^2+3xy-2y^2+7y-y+3因式分解2x^2+3xy-2y^2+7y-y+3因式分解2x^2+3xy-2y^2+7y-y+3因式分解双十字相乘法原式=2x^2(3y-4)x-(2y-3)(
2x^2+3xy-2y^2+7y-y+3 因式分解
2x^2+3xy-2y^2+7y-y+3 因式分解
2x^2+3xy-2y^2+7y-y+3 因式分解
双十字相乘法原式=2x^2 (3y-4)x-(2y-3)(y-2) =[2x-(y-2)][x (2y-3)] =(2x-y 2)(x 2y-3) 2x^2 3xy-2y^2-4x 7y-6 =(
题目有问题吧,仔细看看
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x*x+xy=3,xy+y*y=2,则x*x+2xy+y*y=________?