1/2x²+2x-1,1/2x²+4x+1,1/2x²-2x 因式分解

1/2x²+2x-1,1/2x²+4x+1,1/2x²-2x 因式分解
1/2x²+2x-1,1/2x²+4x+1,1/2x²-2x 因式分解

1/2x²+2x-1,1/2x²+4x+1,1/2x²-2x 因式分解
刚才见别人提问分解因式的题目,
看到题目的数学试卷,
才知道其实是要先把两个多项式求和,
然后再分解因式.
[ (1/2)x" + 2x - 1 ] + [ (1/2)x" + 4x + 1 ]
= x" + 6x
= x( x + 6 )
[ (1/2)x" + 2x - 1 ] + [ (1/2)x" - 2x ]
= x" - 1
= ( x - 1 )( x + 1 )
[ (1/2)x" + 4x + 1 ] + [ (1/2)x" - 2x ]
= x" + 2x + 1
= ( x + 1 )"
像你这样提问,是做不了的.