math question.200pointsLet T denote the temperature at time t.If the temperature is decreasing,is the rate of coling .The great temperature variation during a twelve-hour period occurred in Montana in 1916.When the temperature dropped from 44 to chil
来源：学生作业帮助网 编辑：六六作业网 时间：2024/12/21 08:54:23
math question.200pointsLet T denote the temperature at time t.If the temperature is decreasing,is the rate of coling .The great temperature variation during a twelve-hour period occurred in Montana in 1916.When the temperature dropped from 44 to chil
math question.200points
Let T denote the temperature at time t.If the temperature is decreasing,is the rate of coling .The great temperature variation during a twelve-hour period occurred in Montana in 1916.When the temperature dropped from 44 to chilling-56.show that the rate of cooling exceeded -8f/h at some time during the period of change.
math question.200pointsLet T denote the temperature at time t.If the temperature is decreasing,is the rate of coling .The great temperature variation during a twelve-hour period occurred in Montana in 1916.When the temperature dropped from 44 to chil
(the least rate of cooling -8f/h) times T (temperature which is 44) is equal to new T (temperature at -56),get 12.5 hours.
但是题目里说的是 12 hours period,那么带入原方程式,因为下降rate至少是 -8f/h,所以求出新 的 cooling rate is -8.3333f/h
Hope it helps!
Because the rate of cooling within 12 hours are more than -8f/h. suppose t1 is the time.. so get the following fomula:
t1=t+[T-(-56)]/(100/12) (-56
大 T 代表温度，小 t 代表时间。若温度以冷却速度下降，1916 年蒙大拿的十二小时温度发生从零上 44 度到零下 56 度的巨变。温度下降速度有时超过每小时 8 度。
下降总数是 44-（-56）=100
下降速度=下降总数÷时间=100÷12=8.33333大于 8 度。
让表示温度时间。如果温度降低，是COLING率。大温度变化在12小时期间发生在蒙大纳1916。当温度从44下降到chilling-56。表明，冷却速率超过系统/小时在一段时间在这期间的变化。