-(2xy-y^2+1/2x^2)-2(1/3xy+1/4y^2-x^2)
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-(2xy-y^2+1/2x^2)-2(1/3xy+1/4y^2-x^2)-(2xy-y^2+1/2x^2)-2(1/3xy+1/4y^2-x^2)-(2xy-y^2+1/2x^2)-2(1/3xy+
-(2xy-y^2+1/2x^2)-2(1/3xy+1/4y^2-x^2)
-(2xy-y^2+1/2x^2)-2(1/3xy+1/4y^2-x^2)
-(2xy-y^2+1/2x^2)-2(1/3xy+1/4y^2-x^2)
-(2xy-y^2+1/2x^2)-2(1/3xy+1/4y^2-x^2)
=-2xy+y^2-1/2x^2-2/3xy-1/2y^2+2x^2
=3x^2/2-8xy/3+y^2/2
-(2xy-y^2+x^2/2)-2(xy/3+y^2/4-x^2)
=-2xy+y^2-x^2/2-2xy/3-y^2/2+2x^2
=-8xy/3+3x^2/2+y^2/2.
.(x+y-2)(x+y-2xy)+(xy-1)^2
(x+y)(x+y+2xy)+(xy+1)(xy-1)(x+y)(x-y)+4(y-1)
x^2-xy/xy-y^2约分
计算3xy[2xy-x(y-2)+x-1]
{(x-y/x^2-2xy+y^2)-(xy+y^2/x^2-y^2)}*(xy/y-1)
(x^2+xy/x-y)/(xy/x-y)计算
1.(xy-1)^2-(x+y-2xy)(2-x-y)2.(x+y)(x+y+2xy)+(xy-1)(xy+1)
(-1/3xy)^2•[xy(2x-y)-2x(xy-y^2)]
xy(xy+1)+xy+3-2(x+y+1/2)-(x+y-1)^2因式分解
(-3分之1xy)的平方×[xy(2x-y)-2x(xy-y的平方)]
已知x+y=1,xy=-2,则x²y+xy²-2xy
因式分解(x+y)(x+y+2xy)+(xy+1)(xy-1)
分解因式(x+y)(x+y+2xy)+(xy+1)(xy-1)
分解因式:(X+Y)*(X+Y+2XY)+(XY+1)*(XY-1)
1-2/x+y=xy,4y+6x=xy.求xy的解?
XY(XY+3)+(XY+4)+4(X+Y+1)-(X+Y+2)
若1/x-1/y=2,求3x-2xy-3y/x-xy-y的值3x-2xy-3y/x-xy-y 不好意思,是3x-2xy-3y/x-2xy-y
(-x-y)(x^2+xy+y^2)