分解因式(x+y)²-(x+y)=

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分解因式(x+y)²-(x+y)=分解因式(x+y)²-(x+y)=分解因式(x+y)²-(x+y)==(x+y)[(x+y)-1]=(x+y)(x+y-1)原式=(x+

分解因式(x+y)²-(x+y)=
分解因式(x+y)²-(x+y)=

分解因式(x+y)²-(x+y)=
=(x+y)[(x+y)-1]
=(x+y)(x+y-1)

原式=(x+y)[(x+y)-1]
=(x+y)(x+y-1)