求函数y=-tan(3x+π/6)的单调区间

求函数y=-tan(3x+π/6)的单调区间
求函数y=-tan(3x+π/6)的单调区间

求函数y=-tan(3x+π/6)的单调区间
∵y=-tanx在(-π/2+kπ,π/2+kπ),k∈Z上单调递增
∴-π/2+kπ＜3x+π/6＜π/2+kπ
∴-2π/9+kπ/3＜x＜π/9+kπ/3,k∈Z
∴y=-tan(3x+π/6在(-2π/9+kπ/3,π/9+kπ/3),k∈Z上单调递减
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-π/2+kπ于大3x+π/6小于π/2+kπ
解即可得