计算:1/2+1/4+1/8+1/16+1/32+1/64+1/128+1/256+……+1/2^n

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计算:1/2+1/4+1/8+1/16+1/32+1/64+1/128+1/256+……+1/2^n计算:1/2+1/4+1/8+1/16+1/32+1/64+1/128+1/256+……+1/2^n

计算:1/2+1/4+1/8+1/16+1/32+1/64+1/128+1/256+……+1/2^n
计算:1/2+1/4+1/8+1/16+1/32+1/64+1/128+1/256+……+1/2^n

计算:1/2+1/4+1/8+1/16+1/32+1/64+1/128+1/256+……+1/2^n
因为这个是一个以1/2为首项,1/2为公比的等比数列
所以上式等于1/2【1-(1/2)^n】/(1-1/2)=1-1/2^n

等于1
S=a1/(1-q)=1/2 /(1-1/2)=1

1-1/2^n