若m^2+3m-1=0,则【(m-3)/(3m^2-6)】除以【(m+2)-(5)/(m-2)】

来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/17 12:45:13
若m^2+3m-1=0,则【(m-3)/(3m^2-6)】除以【(m+2)-(5)/(m-2)】若m^2+3m-1=0,则【(m-3)/(3m^2-6)】除以【(m+2)-(5)/(m-2)】若m^2

若m^2+3m-1=0,则【(m-3)/(3m^2-6)】除以【(m+2)-(5)/(m-2)】
若m^2+3m-1=0,则【(m-3)/(3m^2-6)】除以【(m+2)-(5)/(m-2)】

若m^2+3m-1=0,则【(m-3)/(3m^2-6)】除以【(m+2)-(5)/(m-2)】
m^2+3m-1=0,m^2=1-3m
【(m-3)/(3m^2-6)】除以【(m+2)-(5)/(m-2)】
=[(m-3)/(3(m^2-2))] / [(m+2)-5/(m-2)]
=[(m-3)/(3(1-3m-2))] / [(m^2-4-5)/(m-2)]
=-[(m-3)/(3(3m+1))] / (m+3)(m-3)/(m-2)]
=-[(m-3)/(3(3m+1))] * [(m-2)/((m+3)(m-3))]
=-(m-2)/[3(3m+1)(m+3)]
=-(m-2)/[3(3m^2+10m+3)]
=-(m-2)/[3(3-9m+10m+3)]
=-(m-2)/[3(m+6)]