一道国外的物理题,应该属于很简单的,很着急,Lasse (mass 55 kg) skiesLasse (mass 55 kg) skies downhill along a slope which is 45 m long and has anangle of inclination of 17\x0e.The kinetic coefficient of friction between Lasse’s skie

一道国外的物理题,应该属于很简单的,很着急,Lasse (mass 55 kg) skiesLasse (mass 55 kg) skies downhill along a slope which is 45 m long and has anangle of inclination of 17\x0e.The kinetic coefficient of friction between Lasse’s skie
一道国外的物理题,应该属于很简单的,很着急,Lasse (mass 55 kg) skies
Lasse (mass 55 kg) skies downhill along a slope which is 45 m long and has an
angle of inclination of 17\x0e.The kinetic coefficient of friction between Lasse’s skies
and the snow is 0.16.The temperature for both the snow and the air is 0 \x0eC.
a) What is Lasse’s speed at the bottom of the slope,if he starts from rest?Air
resistance is neglected.
b) How far does Lasse slide along the horizontal section after the slope?
c) What is the maximum amount of snow that may melt under Lasse’s skies?

一道国外的物理题,应该属于很简单的,很着急,Lasse (mass 55 kg) skiesLasse (mass 55 kg) skies downhill along a slope which is 45 m long and has anangle of inclination of 17\x0e.The kinetic coefficient of friction between Lasse’s skie
就是55KG的lasse沿17度斜坡下滑,坡长45m,动摩擦系数为0.16,雪和空气均为0度.
蒋势能转变为动能和热（摩擦做功）缺少一个冰的融化热
1、mgh＝mg*45*sin17＝0.5*m*V*V+45*mg*cos17*0.16,计算出即可
2、从1 得出的速度后动能转化为热
0.5 m*V*V＝mg*0.16*水平位移 计算出即可
3、直接能量守恒得出,mgh＝mg*45*sin17＝融化热*质量,假设冰刚好熔化为0度的冰.

请用中文，“外国佬”！！！

一楼这位老师翻译出来了，求动能，用动能定理，,产生的热，等于克服摩擦力做的功 ，不缺条件

嗯 基本就是2 楼这样

a)坡度与长度可知，坡的垂直高度是h=45*sin17,当静止滑动时，水平初速度为0，则根据受力分析，知在沿着坡向上的摩擦力为：f=0.16*mg*cos17.沿着坡面向下的力为F=mg*sin17.则在坡底是速度为设为v，由做功公式得：1/2mv^2=mg*45*cos17-f*45。b)当到达坡底时的速度为v,则由做功得：0-1/2mv^2=-0.16*mg*s(s为下坡后水平滑动距离)。c)...

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a)坡度与长度可知，坡的垂直高度是h=45*sin17,当静止滑动时，水平初速度为0，则根据受力分析，知在沿着坡向上的摩擦力为：f=0.16*mg*cos17.沿着坡面向下的力为F=mg*sin17.则在坡底是速度为设为v，由做功公式得：1/2mv^2=mg*45*cos17-f*45。b)当到达坡底时的速度为v,则由做功得：0-1/2mv^2=-0.16*mg*s(s为下坡后水平滑动距离)。c)摩擦力做功全都转化为热量融化雪：设雪的比热容是c,则可由融化所需要热量的公式就能求得融化雪的质量，具体公式忘了，但是书上应该有这个公式

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