sin(a+b)=1/2,sin(a-b)=1/3,则tana*cotb=?还有道tana=2,求sin^2a-sinacosa-cos^2a=

懂得进.证明,sina+sin(a+b)+sin(a+2b)+...sin(a+nb)=sin(a+ab/2)sin[(n+1)b/2]/sin(b/2) 证明sin(a+b)sin(a-b)=sin^2 a-sin^2 b, 求证:sin(a+b)sin(a-b)=sin^2a-sin^2b 证明 sin^2A+sin^2B-sin^2A*sin^2B+cos^2A*cos^2证明 sin^2A+sin^2B-sin^2A*sin^2B+cos^2A*cos^2B=1 【证明】Sin A+sin B=2Sin 22 已知sin(a)=2sin(b)求sin(a/2)/sin(b/2)的值. 3 在三角形ABC中,已知（a2+b2）sin（A-B）=（a2-b2）sin(A+B) 求证：ABC是等腰或直角三角形(a^2+b^2)sin(A-B)=(a^2-b^2)sin(A+B),(sin^A+sin^B)sin(A-B)=(sin^A-sin^B)sin(A+B) sin^A*(sin(A+B)-sin(A-B))=sin^B*(sin(A-B)+sin(A+B)) sin^A*2c 证明sina sin(a+2b) - sinb sin(b+2a) =sin(a+b)sin(a-b) 在△ABC中,求证；sin^(A/2)+sin^(B/2)+sin^(C/2)=1-2sin(A/2)sin(B/2)sin(C/2） 1:sin(a-b)=sin(-b+a)2:sin(a-b)=sin(-（b-a）),这个为什么是这样的?知识点忘了. 三角形ABC中,A,B为锐角,sin(A+B)=sinA^2+sinB^2,判断三角形ABC的形状因为 (sin A)^2 +(sin B)^2 =sin (A+B)=sin A cos B +sin B cos A,所以 sin A (sin A -cos B) +sin B (sin B -cos A) =0.(*)又因为 A,B 为锐角,所以 sin A>0,sin B>0.(1) 3sin(a)^2+2sin(b)^2=1,3sin(a)=2sin(b),a,b都为锐角,求a+2b的值是3sin(2a)=2sin(2b), 如何证明sin(a+b)sin(a-b)=sin*a-sin*b (*为平方) 求证恒等式sin(A+B)sin(A-B)=sin²A-sin²B sin a-sin b等于 设A,B为锐角,且sin^2A+sin^B=sin(A+B),求证A+B＝90sin^2A+sin^2B=sin(A+B)sin^2A表示sinA的平方 求证(a^2+b^2-c^2)/(b^2+c^2-a^2)=(sin(A+B)+sin(A-B))/(sin(A+B)-sin(A-B)) 求证.(2),sin平方a+sin平方b-sin平方a*sin平方b+cos平方a*cos平方b=1