4*(x-y+1)+y*(y-2*x)=(分解因式)
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4*(x-y+1)+y*(y-2*x)=(分解因式)4*(x-y+1)+y*(y-2*x)=(分解因式)4*(x-y+1)+y*(y-2*x)=(分解因式)4*(x-y+1)+y*(y-2*x)==4
4*(x-y+1)+y*(y-2*x)=(分解因式)
4*(x-y+1)+y*(y-2*x)=(分解因式)
4*(x-y+1)+y*(y-2*x)=(分解因式)
4*(x-y+1)+y*(y-2*x)= =4x-4y+4+y^2-2xy =(4x-2xy)+(y^2-4y+4) =2x(2-y)+(2-y)^2 =(2x+2-y)(2-y) 答题不容易,
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(x+y)(x-y)+4(y-1)
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[(2x+y)^2+(y+2x)(y-2x)-2y(4x-y)]/4y,其中x=1/2,y=1/3
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(x-4y)(2x+y)=
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