2/(3^x)+1)+2/(3^-x)+1)=请告诉我解题步骤
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2/(3^x)+1)+2/(3^-x)+1)=请告诉我解题步骤2/(3^x)+1)+2/(3^-x)+1)=请告诉我解题步骤2/(3^x)+1)+2/(3^-x)+1)=请告诉我解题步骤二楼有人给你解
2/(3^x)+1)+2/(3^-x)+1)=请告诉我解题步骤
2/(3^x)+1)+2/(3^-x)+1)=请告诉我解题步骤
2/(3^x)+1)+2/(3^-x)+1)=请告诉我解题步骤
二楼有人给你解了,我就不用多说了.
详
2/(3^x)+1)+2/(3^-x)+1)
=2/[3^(x)+1]+2/[3^(-x)+1]
=2/[3^(x)+1]+2/[1/3^(x)+1]
=2/[3^x+1]+2/[(1+3^x)/3^x]
=2/[3^x+1]+2*3^(x)/[ 3^x+1]
=(2+2*3^x)/[3^x+1]
=2(3^x+1)/(3^x+1)
=2
祝你好运
吉林 汪清LLX
括号不对
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