(x^6-x+1)^6展开后得ax^12+bx^11+cx^10+dx^9+ex^8+fx^7+gx^6+hx^5+ix^4+jx^3+kx^2+lx+m,则a+c+e+g+i+k+m=
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(x^6-x+1)^6展开后得ax^12+bx^11+cx^10+dx^9+ex^8+fx^7+gx^6+hx^5+ix^4+jx^3+kx^2+lx+m,则a+c+e+g+i+k+m=(x^6-x+
(x^6-x+1)^6展开后得ax^12+bx^11+cx^10+dx^9+ex^8+fx^7+gx^6+hx^5+ix^4+jx^3+kx^2+lx+m,则a+c+e+g+i+k+m=
(x^6-x+1)^6展开后得ax^12+bx^11+cx^10+dx^9+ex^8+fx^7+gx^6+hx^5+ix^4+jx^3+kx^2+lx+m,则a+c+e+g+i+k+m=
(x^6-x+1)^6展开后得ax^12+bx^11+cx^10+dx^9+ex^8+fx^7+gx^6+hx^5+ix^4+jx^3+kx^2+lx+m,则a+c+e+g+i+k+m=
f(x)=(x^6-x+1)^6
f(1) =a+b+c+d+e+f+g+h+i+j+k+l+m
f(-1)=a-b+c-d+e-f+g-h+i-j+k-l+m
所以
a+c+e+g+i+k+m=(f(1)+f(-1))/2=(1+3^6)/2