如果(x^3-3a+x^3/1）^2+(x+2b+x/1)^2=0,求3a+2b（4b^2-3)的值

如果(x^3-3a+x^3/1）^2+(x+2b+x/1)^2=0,求3a+2b（4b^2-3)的值
如果(x^3-3a+x^3/1）^2+(x+2b+x/1)^2=0,求3a+2b（4b^2-3)的值

如果(x^3-3a+x^3/1）^2+(x+2b+x/1)^2=0,求3a+2b（4b^2-3)的值
(x^3-3a+x^3/1）^2+(x+2b+x/1)^2=0
x^3-3a+x^3/1=0 x+2b+x/1=0
x^3+x^3/1=3a
(x+1/x)(x^2-1+1/x^2)=3a
(x+1/x)(x^2+2-3+1/x^2)=3a
(x+1/x)((x+1/x)^2-3)=3a (1)
x+2b+x/1=0
x+x/1=-2b (2)
将(2)代入(1)得
-2b(4b^2-3)=3a
3a+2b(4b^2-3)=0