分解因式:x²-y²-x+y=__ a²-2ab+b²-1=

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分解因式:x²-y²-x+y=____________a²-2ab+b²-1=__________分解因式:x²-y²-x+y=______

分解因式:x²-y²-x+y=____________ a²-2ab+b²-1=__________
分解因式:x²-y²-x+y=____________ a²-2ab+b²-1=__________

分解因式:x²-y²-x+y=____________ a²-2ab+b²-1=__________
解
x²-y²-x+y
=(x-y)(x+y)-(x-y)
=(x-y)(x+y-1)
a²-2ab+b²-1
=(a-b)²-1²
=(a-b+1)(a-b-1)
x²-y²-x+y=__(x-y)(x+y-1)_ a²-2ab+b²-1=___(a-b-1)(a-b+1)____

x²-y²-x+y
=(x²-y²)-(x-y)
=(x+y)(x-y)-(x-y)
=(x-y)(x+y-1)

a²-2ab+b²-1
=(a-b)²-1
=(a-b+1)(a-b-1)