已知x=根2-1 求（x+1/x²-x - x/x²-2x+1）÷1/x的值

已知x=根2-1 求（x+1/x²-x - x/x²-2x+1）÷1/x的值
已知x=根2-1 求（x+1/x²-x - x/x²-2x+1）÷1/x的值

已知x=根2-1 求（x+1/x²-x - x/x²-2x+1）÷1/x的值
（x+1/x²-x - x/x²-2x+1）÷1/x
=(x²-1-x²/x(x-1)²)÷1/x
=-1/x(x-1)² *x
=-1/(x-1)²
=-1/（根号2-2 ）²
=-1/6-4根号2
=-6-4根号2/4
=-3-2根号2/2