求过L1:2x+y-5=0和L2:4x+y-9=0的交点,且平行于L3:x+2y-5=0的直线方程∵2x+y-5=4x+y-9 => x=7,y=-9∴直线L1与直线L2的交点为A(7,-9)∵x+2y-5=0∴y= -1/2x+5/2 => k=-1/2∵设该直线为L4:y=-1/2x+b∴代入点A得 -9= -7/2+b => b= -1
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求过L1:2x+y-5=0和L2:4x+y-9=0的交点,且平行于L3:x+2y-5=0的直线方程∵2x+y-5=4x+y-9 => x=7,y=-9∴直线L1与直线L2的交点为A(7,-9)∵x+2y-5=0∴y= -1/2x+5/2 => k=-1/2∵设该直线为L4:y=-1/2x+b∴代入点A得 -9= -7/2+b => b= -1
求过L1:2x+y-5=0和L2:4x+y-9=0的交点,且平行于L3:x+2y-5=0的直线方程
∵2x+y-5=4x+y-9 => x=7,y=-9
∴直线L1与直线L2的交点为A(7,-9)
∵x+2y-5=0
∴y= -1/2x+5/2 => k=-1/2
∵设该直线为L4:y=-1/2x+b
∴代入点A得 -9= -7/2+b => b= -11/2
即L4:x+2y+11=0
求过L1:2x+y-5=0和L2:4x+y-9=0的交点,且平行于L3:x+2y-5=0的直线方程∵2x+y-5=4x+y-9 => x=7,y=-9∴直线L1与直线L2的交点为A(7,-9)∵x+2y-5=0∴y= -1/2x+5/2 => k=-1/2∵设该直线为L4:y=-1/2x+b∴代入点A得 -9= -7/2+b => b= -1
∵2x+y-5=4x+y-9 => x=7,y=-9 这里解方程错了,得到的是x=2 y=1
∴直线L1与直线L2的交点为A(7,-9)
∵x+2y-5=0
∴y= -1/2x+5/2 => k=-1/2
∵设该直线为L4:y=-1/2x+b
∴代入点A得 -9= -7/2+b => b= -11/2
即L4:x+2y+11=0
由于交点错了,后面也就随之错了
第一步就有问题啊 依你的答案 x=7,y=-9的时候
2x+y-5=0,4x+y-9=10
正确答案
2x+y-5=4x+y-9=> x=2,y=1
后面方法你继续做下去即可
∵2x+y-5=4x+y-9 => x=2,y=1
∴直线L1与直线L2的交点为A(2,1)
∵x+2y-5=0
∴y= -1/2x+5/2 => k=-1/2
∵设该直线为L4:y=-1/2x+b
∴代入点A得 1= -2/2+b => b=2
即L4: x+2y-4=0