设Sn,Tn分别是等差数列an,bn的前n项和,已知Sn/Tn=2n+1/4n-2,则a10+a11/b10+b11=
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设Sn,Tn分别是等差数列an,bn的前n项和,已知Sn/Tn=2n+1/4n-2,则a10+a11/b10+b11=设Sn,Tn分别是等差数列an,bn的前n项和,已知Sn/Tn=2n+1/4n-2
设Sn,Tn分别是等差数列an,bn的前n项和,已知Sn/Tn=2n+1/4n-2,则a10+a11/b10+b11=
设Sn,Tn分别是等差数列an,bn的前n项和,已知Sn/Tn=2n+1/4n-2,则a10+a11/b10+b11=
设Sn,Tn分别是等差数列an,bn的前n项和,已知Sn/Tn=2n+1/4n-2,则a10+a11/b10+b11=
(a10+a11)/(b10+b11)
=10(a10+a11)/[10(b10+b11)]
=[(a1+a20)+(a2+a19)+...+(a10+a11)]/[(b1+b20)+(b2+b19)+...+(b10+b11)]
=S20/T20
=(2×20+1)/(4×20-2)
=41/78
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设等差数列{an},{bn}的前n项和分别是Sn,Tn,且Sn/Tn=7n+2/n+3求a7/b7有助于回答者给出准确的答案