设f(θ)=sin(3/π-2θ)+cos(π/3+2θ).求证:当θ=kπ-π/8(k∈Z)时,f(θ)的最大值为(√2+√6)/2要过程啊~~~在线等啊~~急~~~

设函数f(x)=-x^2+x+7,若不等式f(3+2sinθ) 设f(x)=根号1-x化简f(sin2)+f(sin(-2))1.设f(x)=根号1-x化简f(sin2)+f(sin(-2))2.已知tanθ=2,求2sinθ的平方+3sin2θ+13.若sinθ:sinθ/2=8:5求cosθ 设f(x)=sinπx/3,求f(1)+f(2)+f(3)+...+f(2011)的值RT 设函数f(x)=sinπ/6（x),则f(1)+f(2)+f(3)+…f(2008)=? 设函数f(x)=sinπ/6（x),则f(1)+f(2)+f(3)+…f(2008)=? 设f(x)=sinπ/3x,求f(1)+f(2)+……+f(2011)急需啊 设f(x)=sinπ/3x,求f(1)+f(2)+...+f(72)的值 设函数f(x)=(sinθ/3)x^3+((根号3)cosθ/2)x^2+tanθ,则f'(π/4)= 设sinθ+cosθ=√2/3,π/2sinθ^3是sinθ的3次 设函数 f(x)=sin(2x+y),(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f x=SIN(2X+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+ φ)(-π