已知y/x=9/10则(1-y/x)[x/(y-x)]?
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已知y/x=9/10则(1-y/x)[x/(y-x)]?已知y/x=9/10则(1-y/x)[x/(y-x)]?已知y/x=9/10则(1-y/x)[x/(y-x)]?(1-9)(x/y-1)x/y变
已知y/x=9/10则(1-y/x)[x/(y-x)]?
已知y/x=9/10则(1-y/x)[x/(y-x)]?
已知y/x=9/10则(1-y/x)[x/(y-x)]?
(1-9)(x/y-1) x/y变成1/9 继续往下算
(1-y/x)[x/(y-x)]=[(x-y)/x][x/(y-x)]=-1