若x-y=2,x^2+y^2=4,则x^2002+y^2002=
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若x-y=2,x^2+y^2=4,则x^2002+y^2002=若x-y=2,x^2+y^2=4,则x^2002+y^2002=若x-y=2,x^2+y^2=4,则x^2002+y^2002=由x-y
若x-y=2,x^2+y^2=4,则x^2002+y^2002=
若x-y=2,x^2+y^2=4,则x^2002+y^2002=
若x-y=2,x^2+y^2=4,则x^2002+y^2002=
由x-y=2,x^2+y^2=4可得:
x-y=2 两边同时平方得:
x^2+y^2-2xy=4
所以:
2xy=0
所以解得:x=0 y=-2,或x=2 y=0
当x=0 y=-2时
x^2002+y^2002
=0^2002+(-2)^2002
=2^2002
当x=2,y=0时
x^2002+y^2002
=2^2002+0^2002
=2^2002
所以x^2002+y^2002=2^2002
(x-y)^2=x^2+y^2-2xy=4-2xy=4
所以 xy=0 故x=0,y=-2 或y=0,x=2
所以原式=2^2002
x-y/x-x+y/y-(x+y)(x-y)/y² y/x=2
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