请问到-1/2≤sin(2x+π/6)≤1这步怎么得到的,谢谢各位了.

请问到-1/2≤sin(2x+π/6)≤1这步怎么得到的,谢谢各位了.
请问到-1/2≤sin(2x+π/6)≤1这步怎么得到的,谢谢各位了.

请问到-1/2≤sin(2x+π/6)≤1这步怎么得到的,谢谢各位了.
x∈[0,π/2]
2x∈[0,π]
2x＋π/6∈[π/6,7π/6]