{x-y=3 2x+3y=11
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{x-y=32x+3y=11{x-y=32x+3y=11{x-y=32x+3y=11x-y=3(1)2x+3y=11(2)(1)式X3,得3x-3y=9(3)(3)式+(2)式得5x=20x=4将x=
{x-y=3 2x+3y=11
{x-y=3 2x+3y=11
{x-y=3 2x+3y=11
x-y=3 (1)
2x+3y=11 (2)
(1)式X3, 得
3x-3y=9 (3)
(3)式+(2)式 得
5x=20
x=4
将x=4代入(1)式
得y=1
答:{x=4 y=1
由x-y=3得,x=y+3
把x=y+3代入2x+3y=11中得 2(y+3)+3y=11,所以y=1
把y=1代入x=y+3中得 x=1+3=4
所以{x=4
y=1
x - y = 3 => x = 3 + y ...①
将①式带入 2x+3y = 11得 2(3+y)+ 3y = 11 => 6+5y = 11 => y =1 从而 x = 4
故该方程组的解为 {x= 4,y=1
x-y=3 得y=x-3(1)
把(1)
代入2x+3y=11 得5x=20得
x=4 (2)
把(2)代入(1)
得y=1
X -Y=3 ① 2X+3y=11 ② 方法1:①×3+②可得:5X=20,故X=4 代入①或②得Y=1 方法2:①×2— ②得:-5Y=-5,故Y=1 代入①或②得X=4 无论如何,关键是乘除消去一个未知数,再代入 原方程即可
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