⒈(x+1)/(x^2-x-6)+3/(5x^2-10+5x)-(x-2)/(x^2-4x+3)⒉1/(x-a)-1/(x+a)-2a/(x^2+a^2)-4a^3/(x^4-a^4)⒊1/(x-2)-1/(x+2)-4(x^2+4)-32/(x^4-16)

来源：学生作业帮助网编辑：六六作业网时间：2024/12/22 16:33:04

⒈(x+1)/(x^2-x-6)+3/(5x^2-10+5x)-(x-2)/(x^2-4x+3)⒉1/(x-a)-1/(x+a)-2a/(x^2+a^2)-4a^3/(x^4-a^4)⒊1/(x-2)

⒈(x+1)/(x^2-x-6)+3/(5x^2-10+5x)-(x-2)/(x^2-4x+3)⒉1/(x-a)-1/(x+a)-2a/(x^2+a^2)-4a^3/(x^4-a^4)⒊1/(x-2)-1/(x+2)-4(x^2+4)-32/(x^4-16)
⒈(x+1)/(x^2-x-6)+3/(5x^2-10+5x)-(x-2)/(x^2-4x+3)
⒉1/(x-a)-1/(x+a)-2a/(x^2+a^2)-4a^3/(x^4-a^4)
⒊1/(x-2)-1/(x+2)-4(x^2+4)-32/(x^4-16)

⒈(x+1)/(x^2-x-6)+3/(5x^2-10+5x)-(x-2)/(x^2-4x+3)⒉1/(x-a)-1/(x+a)-2a/(x^2+a^2)-4a^3/(x^4-a^4)⒊1/(x-2)-1/(x+2)-4(x^2+4)-32/(x^4-16)
1、原式=(x+1)/(x-3)(x+2)+3/[5(x-1)(x+2)]-(x-2)/[(x-1)(x-3)]
=[5(x+1)(x-1)+3(x-3)-(x-2)(x+2)]/[5(x-1)(x+2)(x-3)]
=(5x^2-5+3x-9-x^2+4)/[5(x-1)(x+2)(x-3)]=(4x^2+3x-10)/[5(x-1)(x+2)(x-3)]
=(x+2)(4x-5)/[5(x-1)(x+2)(x-3)]=(4x-5)/[5(x-1)(x-3)]
2、原式=(x+a-x+a)/(x^2-a^2)-2a/(x^2+a^2)-4a^3/(x^4-a^4)
=2a(x^2+a^2-x^2+a^2)/(x^4-a^4)-4a^3/(x^4-a^4)=0
3、原式=(x+2-x+2)/(x^2-4)-4(x^2+4)-32/(x^4-16)
=4(x^2+4-X^2+4)/(x^4-16)-32/(x^4-16)=0

3/(5x^2+5x-10)+(x+1)/(x^2-x-6)-(x-2)/(x^2-4x+3) =3/5(x+2)(x-1)+(x+1)/(x-3)(x+2)-(x-2)/(x-1)(x-3) =[3(x-3)+5(x+1)(x-1)-5(x-2)(x+2)]/5(x+2)(x-1)(x-3) =(3x-9+5x²-5-5x²+20)/5(x+2)(x-1)(x-3) =（3x+6)/5(x+2)(x-1)(x-3) =3/[5...

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