已知cos(a+π/4)=3/5,π/2≤a≤3π/2,求cos(2a+π/4)的值
来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/25 22:32:16
已知cos(a+π/4)=3/5,π/2≤a≤3π/2,求cos(2a+π/4)的值已知cos(a+π/4)=3/5,π/2≤a≤3π/2,求cos(2a+π/4)的值已知cos(a+π/4)=3/5
已知cos(a+π/4)=3/5,π/2≤a≤3π/2,求cos(2a+π/4)的值
已知cos(a+π/4)=3/5,π/2≤a≤3π/2,求cos(2a+π/4)的值
已知cos(a+π/4)=3/5,π/2≤a≤3π/2,求cos(2a+π/4)的值
∵π/2≤a≤3π/2
∴cos(a+π/4)=3/5>0
∵a+π/4>3π/2
∴3π/2sin(a+π/4)=-√[1-cos²(a+π/4)]=-4/5
sina=[sin(a+π/4)-π/4]=√2/2*[sin(a+π/4)-cos(a+π/4)]=√2/2*(-4/5-3/5)=-7√2/10
cosa=-√(1-sin²a)=-√2/10
cos2a=2cos²a-1=-24/25,sin2a=2sinacosa=7/25
∴cos(2a+π/4)=√2/2(cos2a-sin2a)=-31√2/5
已知cos(a+b)=4/5,cos(a-b)=-4/5,3π/2
.已知Cos(a+b)=4/5,cos(a-b)= -4/5,3/2π
已知cos(a+π/4)=3/5,π/2
已知sin(3π+a)=1/4,求[cos(π+a)]/{cosa[cos(π+a)-1]}+[cos(a-2π)]/[cos(a+2π)cos(π+a)+cos(-a)]的值要具体过程
已知cos(π-a)*cos(3π/2+a)=-1/8,且π/4
急::已知sin(3π+a)=2cos(a-4π),求(5sin(π/2+a)+cos(π/2-a))/(2cos(π+a)-sin(-a))的值已知sin(3π+a)=2cos(a-4π),求(5sin(π/2+a)+cos(π/2-a))/(2cos(π+a)-sin(-a))的值在线 急求帮助! 有答必采~~~~
已知sin(a-π)=2cos(2π-a),求(sin(π-a)+5cos(2π-a))/(3cos(π-a)-sin(-a))的值.
已知sin(a-π)=2cos(2π-a),求sin(π-a)+5cos(2π-a)/3cos(π-a)+sin(-a)的值.
已知cos(a+?π)=3/5,π/2≤a<3π/2.求cos2a.更改:已知cos(a+π/4)=3/5
已知3sin(π +a)+cos(-a)/4sin(-a)-cos(9π +a)=2,求tana的值
已知(sin a+sin 2a+ sin3a)/(cos a+cos 2a+cos 3a)=-4/tana.且π
已知cos(π/4-a)=-3/5,π/2≤a≤π,求cosa
已知sina =3/5 a∈(π/2,π) 求cos(π/4-a)
已知cos(π/6-a)=1/3,则cos(5π/6+a)sin(2π/3-a=?
已知cosa=-4/5,a是第二象限角,求cos(a+π/3)和cos(a-π/3).
三角函数计算的已知cos(a+π/4)=3/5,π/2≤a
已知sin^4a-cos^4a=-3/5,3π/2
已知cos(π/2+a)=2sin(a-π/2),求sin(π-a)+cos(a+π)/求sin(π-a)+cos(a+π)/5cos(5π/2-a)+3sin(7π/2-a)