若x-y=2,x^2=y^2=4,求x^2002=y^2002
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若x-y=2,x^2=y^2=4,求x^2002=y^2002若x-y=2,x^2=y^2=4,求x^2002=y^2002若x-y=2,x^2=y^2=4,求x^2002=y^2002∵x^2=y^
若x-y=2,x^2=y^2=4,求x^2002=y^2002
若x-y=2,x^2=y^2=4,求x^2002=y^2002
若x-y=2,x^2=y^2=4,求x^2002=y^2002
∵x^2=y^2,x-y=2
∴±x=±y,X≠y
∴x,y互为相反数.
∴得到方程x+y=0
∴x+y=0
x-y=2
解得x=1,y=-1
∴x^2002=1^2002=1
y^2002=(-1)^2002=1
∴x^2002=y^2002
题目错误
我也觉得题目错了
x^2=y^2=4的话要么x=±2,要么y=±2,
怎么可能x-y=2,
就算是复数也不可能阿
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