1.y=〔sin(2x-1)+2〕^32.y=(x+1)^4(x-2)^4

1.y=〔sin(2x-1)+2〕^32.y=(x+1)^4(x-2)^4
1.y=〔sin(2x-1)+2〕^3
2.y=(x+1)^4(x-2)^4

1.y=〔sin(2x-1)+2〕^32.y=(x+1)^4(x-2)^4
y’=3（sin(2x-1)+2〕^2*【sin(2x-1)+2】’
=3（sin(2x-1)+2〕^2*（2cos（2x-1））
=6（sin(2x-1)+2〕^2*cos(2x-1)
y'=(x+1)^4[(x-2)^4]'+[(x+1)^4]'(x-2)^4
=4(x+1)^4(x-2)^3+4(x+1)^3(x-2)^4
=4(x+1)^3(x-2)^3 (2x-1)

1.y'=3[sin(2x-1)+2]^2 *cos(2x-1)*2
=6[sin(2x-1)+2]^2 cos(2x-1)
2.y=(x^2-x-2)^4
y'=4(x^2-x-2)^3(2x-1)
=12(2x-1)(x+1)^3(x-2)^3

1)y={3[sin(2x-1)+2]^2}*cos(2x-1)*2
2)y=4(x+1)^4(x-2)^4+4(x+1)^4(x-2)^3