(x-2)2+|y+3|=0则=?
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(x-2)2+|y+3|=0则=?(x-2)2+|y+3|=0则=?(x-2)2+|y+3|=0则=?解析绝对值大于等于0所以x-2=0x=2y+3=0y=-3(-3)²=9(x-2)2+|
(x-2)2+|y+3|=0则=?
(x-2)2+|y+3|=0
则
=?
(x-2)2+|y+3|=0则=?
解析
绝对值大于等于0
所以
x-2=0
x=2
y+3=0
y=-3
(-3)²=9
(x-2)2+|y+3|=0
∴﹛x-2=0
y+3=0
∴x=2, y=-3
y^x=(-3)²=9
解:根据题意得
x-2=0
y+3=0
∴x=2
y=-3
∴y的x次方=(-3)²=9
因为 (x--2)^2+Iy+3I=0,
所以 x=2, y=--3,
所以 y^x=(--3)^2
=9。
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