若f(x)=ax³-bx-1,且f(-2)=8,求f(2)的值

若f(x)=ax³-bx-1,且f(-2)=8,求f(2)的值
若f(x)=ax³-bx-1,且f(-2)=8,求f(2)的值

若f(x)=ax³-bx-1,且f(-2)=8,求f(2)的值
f(x)=ax³-bx-1,f(x)+1=ax³-bx
f(-2)=8,f(2)+1=-f(-2)-1=-9
f(2)=-10

f(-2)=-8a+2b-1=8
8a-2b=-9
f(2)
=8a-2b-1
=-9-1
=-10

f(x)+1为奇函数
f(-2)+1=9
所以f(2)+1=-9
f(2)=-10