1/3[(2a+3b)+1/2a-2/3(6a-5b)]=?1/2（2a-4b+c）+（a+3b-c）=?

1/3[(2a+3b)+1/2a-2/3(6a-5b)]=?1/2（2a-4b+c）+（a+3b-c）=?
1/3[(2a+3b)+1/2a-2/3(6a-5b)]=?
1/2（2a-4b+c）+（a+3b-c）=?

1/3[(2a+3b)+1/2a-2/3(6a-5b)]=?1/2（2a-4b+c）+（a+3b-c）=?
1)1/3[(2a+3b)+1/2a-2/3(6a-5b)]
=1/3*[2a+3b+1/2a-4a+10/3b]
=1/3*[-3/2a+19/3b]
=-1/2a+19/9b
2)1/2（2a-4b+c）+（a+3b-c）
=a-2b+1/2c+a+3b-c
=2a-b-1/2c

1/3[(2a+3b)+1/2a-2/3(6a-5b)]
=1/3(2a+3b+a/2-4a+10b/3)
=1/3(-3a/2+19b/3)
=-a/2+19b/9

1/2（2a-4b+c）+（a+3b-c）
=a-2b+c/2+a+3b-c
=2a+b-c/2