f(x)=2sinπ/4cosπ/4- 2根号3sin^2π/4+根号3

来源：学生作业帮助网编辑：六六作业网时间：2024/07/08 04:02:26

f(x)=2sinπ/4cosπ/4-2根号3sin^2π/4+根号3f(x)=2sinπ/4cosπ/4-2根号3sin^2π/4+根号3f(x)=2sinπ/4cosπ/4-2根号3sin^2π/

f(x)=2sinπ/4cosπ/4- 2根号3sin^2π/4+根号3
f(x)=2sinπ/4cosπ/4- 2根号3sin^2π/4+根号3

f(x)=2sinπ/4cosπ/4- 2根号3sin^2π/4+根号3
原式=f(x)=sinπ/2-2√3(√2/2)^2+√3
=1-2√3×1/2+√3
=1-√3+√3
=1