[a/2+b/2]^2+[a/2-b/2]^2=
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[a/2+b/2]^2+[a/2-b/2]^2=[a/2+b/2]^2+[a/2-b/2]^2=[a/2+b/2]^2+[a/2-b/2]^2=[a/2+b/2]^2+[a/2-b/2]^2=2*[(
[a/2+b/2]^2+[a/2-b/2]^2=
[a/2+b/2]^2+[a/2-b/2]^2=
[a/2+b/2]^2+[a/2-b/2]^2=
[a/2+b/2]^2+[a/2-b/2]^2
=2*[(a/2)^2+(b/2)^2]
=a^2/2+b^2/2
直接展开就可以了，答案：（a^2+b^2）/2
-2a(a+b)+b(a+b)
(a+2b)(a-2b)+(a-b)(a+b)-2(a-3b)(a-b)
5(a*a*b-3*a*a*b)-2*(a*a*b-7*a*b*b)
-a-b+2b^2/a+b
化简：|a+b|+|b-a|+|2b|
|a+b|-|b-a|+|2b|化简哦!
a-b+2b²/a+b
通分a-b,2b^/a+b
化简(2a-b/a+b-b/a-b)除以a-2b/a+b
计算：((a+b)(a-b)-(a-b)^2+2b(a-b))/4(a-b)
化简(2a-b/a+b-b/a-b)除以a-2b/a +b
化简：{[(2a-b)/(a+b)]-[b/(a-b)]}÷[(a-2b)/(a+b)]
计算·[(2a+-b)/(a+b)-b/(a+b)]/(a-2b)/(a+b)
(2a-3b)[(a+b)-b(a-3b)]
(a-b)(a+b)²-(a+b)(a-b)²+2b(a²+b²)
(a-b)(a+b)²-(a+b)(a-b)²+2b(a²+b²)
化简：a-[b-2a-(a-b)]
化简（2a-b/a+b-b/a-b）÷a-2a/a-b