{x-y+(4xy/x-y)}{x+y-(4xy/x+y)}怎么解?/是分数线,第一个式子中分子是4xy,分母是x-y；第二式中分子是4xy,分母是x+y.

|x|/x+y/|y|+xy/|xy|= 计算下面式子{x-y+[(4xy)/(x-y)]}{x-y-[(4xy)/(x-y)]} （x-y+4xy/x-y）(x+y-4xy/x-y) (x-y+4xy/x+y)(x+y-4xy/x+y)等于的多少? 谢谢! 化简计算:[x-y+4xy/(x-y)] * [x+y-4xy/(x+y)] 计算:[x-y+4xy/(x-y)] * [x+y-4xy/(x+y)] 化简[x-y+4xy/(x-y)][x+y-4xy/(x-y)] 计算：（x-y+4xy/x-y)(x+y-4xy/x+y) (x一y+4xy/x-y)(x+y-4xy/x+y) 化简:(x+y-4xy/x+y)*(x-y-4xy/x-y)= (x-y+(4xy/x-y))(x+y-(4xy/x+y)) 分式计算 因式分解:12xy^2(y-x)+xy^3(x-y)+4x^2y(x-y) xy(x-y)-x(x-y)² 计算:2xy/(x+y)².(x+y)/4y (x+y)(x+y+2xy)+(xy+1)(xy-1)(x+y)(x-y)+4(y-1) -x-3xy+y xy-1+x-y 集合{(x,y)|xy