x^2+y^2+2xy-z^2
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x^2+y^2+2xy-z^2x^2+y^2+2xy-z^2x^2+y^2+2xy-z^2原式=(x+y)^2-z^2=(x+y+z)(x+y-z)赞同原式=(x+y)^2-z^2=(x+y+z)(x
x^2+y^2+2xy-z^2
x^2+y^2+2xy-z^2
x^2+y^2+2xy-z^2
原式=(x+y)^2-z^2
=(x+y+z)(x+y-z)
赞同原式=(x+y)^2-z^2
=(x+y+z)(x+y-z)
代数 x^-y^/ x^-(y-z)^ 除以 x^+2xy+y^/(x-y)^-z^ 乘 x^+xy-xz/x^-xy
化简(y-x)(z-x)/(x-2y+z)(x+y-2z)+(z-y)(x-y)/(xy-2z)(y+z-2x)+(x-z)(y-z)/(y+z-2x)(x-2y+z)速速回答
化简x^2-yz/[x^2-(y+z)x+yz]+y^2-zx/[y^2-(z+x)y+zx]+z^2-xy/[z^2-(x+y)z+xy]
(2X+Z-Y)/(X^2-XY+XZ-YZ)-(Y-Z)/(X^2-XY-XZ+YZ)
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设z=f(x^2-y^2,e^(xy)),求偏导z/x,偏导z/y
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24xy^2z^2(x+y+z)-32xyz(z-x-y)^2+8xyz^3(z-x-y)
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(x^2+yz)/(x^2+x(y-z)-yz)+(y^2-xz)/(y^2+y(x+z)+zx)+(z^2+yx)/(x^2-z(x-y)-yx)最后一项应为:(z^2-xy)/(z^2+z(y-x)-xy)
二元函数Z=x^2-xy+4y^2,求二阶偏导数Zxx Zxy Zyy
(x^2-y^2)/[x^2-(y-z)^2]/[x^2+2xy+y^2]/[(x-y)^2-z^2]*[x^2+xy-xz]/[x^2-xy]=
求全微分函数Z(X,Y),已知方程 Z^2*ln(X+Z)=XY
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