.- -1 因式分解:(x²+2x+1)²-y²

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.--1因式分解:(x²+2x+1)²-y².--1因式分解:(x²+2x+1)²-y².--1因式分解:(x²+2x+1)&su

.- -1 因式分解:(x²+2x+1)²-y²
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1 因式分解:(x²+2x+1)²-y²

.- -1 因式分解:(x²+2x+1)²-y²
(x²+2x+1)²-y²
=(x²+2x+1+y)(x²+2x+1-y)
=((x+1)²+y)((x+1)²-y)
=(x+1)²(y-y)
=(x+1)²

实数范围?

貌似x²+2x+1=(x+1)² 所以这道题的结果是(x+1)的四次方-y²

(x²+2x+1)²-y² =(x+1)² -y² =(x²+2x+y+1)(x²+2x-y+1)