设等差数列{an}的前n项和Sn,且S15>0,S16

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设等差数列{an}的前n项和Sn,且S15>0,S16设等差数列{an}的前n项和Sn,且S15>0,S16设等差数列{an}的前n项和Sn,且S15>0,S16S15>0S15=15a8>0a8>0

设等差数列{an}的前n项和Sn,且S15>0,S16
设等差数列{an}的前n项和Sn,且S15>0,S16

设等差数列{an}的前n项和Sn,且S15>0,S16
S15>0 S15=15a8>0 a8>0
S16

(a1+a15)*15/2>0 → 2a1+14d>0 → d>-1/7a1
(a1+a16)*16/2<0 → 2a1+15d<0 → d<-2/15a1
∴-1/7a1<-2/15a1
a1>0,d<0
Sn/an=n(2a1+nd-d)/[2(a1+nd-d)]
(Sn/an)'={[n(a1+nd-d)+na1]/[2(a1+nd-d)]}'

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(a1+a15)*15/2>0 → 2a1+14d>0 → d>-1/7a1
(a1+a16)*16/2<0 → 2a1+15d<0 → d<-2/15a1
∴-1/7a1<-2/15a1
a1>0,d<0
Sn/an=n(2a1+nd-d)/[2(a1+nd-d)]
(Sn/an)'={[n(a1+nd-d)+na1]/[2(a1+nd-d)]}'
=
然后做不下去了……
改我提问另了,没悬赏分的啊,楼上那个,有劳你有空用用电脑,
教教我,你是如何想的
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