换元法：(x-3)/(x+1)+(x+1)/(x-3)=2
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换元法：(x-3)/(x+1)+(x+1)/(x-3)=2换元法：(x-3)/(x+1)+(x+1)/(x-3)=2换元法：(x-3)/(x+1)+(x+1)/(x-3)=2设y=x-3/x+1变为y
换元法：(x-3)/(x+1)+(x+1)/(x-3)=2
换元法：(x-3)/(x+1)+(x+1)/(x-3)=2
换元法：(x-3)/(x+1)+(x+1)/(x-3)=2
设y=x-3/x+1变为y+1/y=2.等号两边同乘y解得y=x-3/x+1=1但x-3/x+1=1无解,所以这个题无解
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x(x+1)(x+2)(x+3)+1 (换元法）
/X-3/-/X-1/
(3x/x-1)
x-3(x-1)
| X+1 |>| X-3 |
x+3/x-1
(x +1)(x-3)
(x+3)(x-1)
|x+1|-|x-3|
(x+1)(x-3)
x+2/x+1-x+3/x+2-x+4/x+3+x+5/x+4
[x（x+1）+x平方（x-1)]+（-3x)
x{x+1}{x-1}}x-2}{x-3}-40
求一个数独答案X X X 9 X X X 8 2 X 6 3 X X 1 4 X 99 X 8 X X X X X XX X X 6 7 X 3 X XX 4 6 X 5 X 2 9 XX X 7 X 2 3 X X XX X X X X X 7 X 17 X 4 3 X X 6 2 X6 3 X X X 7 X X X
x^5-x^4+x^3-x^2+x-1