分解因式;x²-y²-3x-3y=原式=(x+Y)(x-Y)-3(x+Y)后怎么==(x+Y)(x-Y-3)

来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/18 17:01:54
分解因式;x²-y²-3x-3y=原式=(x+Y)(x-Y)-3(x+Y)后怎么==(x+Y)(x-Y-3)分解因式;x²-y²-3x-3y=原式=(x+Y)(

分解因式;x²-y²-3x-3y=原式=(x+Y)(x-Y)-3(x+Y)后怎么==(x+Y)(x-Y-3)
分解因式;x²-y²-3x-3y=
原式=(x+Y)(x-Y)-3(x+Y)
后怎么==(x+Y)(x-Y-3)

分解因式;x²-y²-3x-3y=原式=(x+Y)(x-Y)-3(x+Y)后怎么==(x+Y)(x-Y-3)
x²-y²-3x-3y
=(x+Y)(x-Y)-3(x+Y)
=(x+Y)(x-Y-3)
提取公因式:(x+Y)

提公因式(x+y)就得(x+Y)(x-Y-3)