x\1+y\1=6\1 y\1+z\1=10\1 z\1+x\1=15\2 求这个分式三元一次方程的解题方法?

已知 x/(y+z)+y/(z+x)+z/(x+y)=1求 (x*x)/(y+z)+(y*y)/(x+z)+(z*z)/(x+y)=? x+y+z=6 x+2y+3z=14 y+1=z {x+y-z=11 y+z-x=5 z+x-y=1 {x+y-z=11,x-y-z=-5,x-y+z=1 {x-y+z=6,x+3y=-1,y+2z=3 已知x:y=3:5 y:z=6:1,求x:y:z( ):( ):( ) X/Y+Z=Y/X+Z+1=Z/X+Y-1=X+Y+Z,求x+y+z等于多少 已知实数x y z满足x/(x+1)=y/(y+2)=z/(z+3)=(x+y+z)/3,求x+y+z的值 已知实数x y z满足x/(x+1)=y/(y+2)=z/(z+3)=(x+y+z)/3,求x+y+z的值 (1)X+Y=15,Y+Z=-6,Z+X=7.(2)X+Y=-14,Y+Z=-7,Z+X=9.(3)X+Y=0,Y+Z=-1,Z+X=-1. 分式加减的几道题目求速度1 .(x+y)²/（x-z)(y-z) - (y+z)²/（x-z)(y-z) = 2.2x+3y/x-y+2y/y-x-3y/x-y= (x+y+z)÷10=x+1.1 y+x=z-80+y-1 z-y=8x+y+8 x+z÷y=? x-y+z=-1 5x+2y-z=6 4x-3y+2z=-5 x+y-z=6 x-3y+2z=1 3x+2y-z=4 阿 x+y+z=1 4x+5y-z=6 x+2y-z=3 x+y-z=6,x-3y+2z=1,3x+2y-z=4 x+y-z=6 x-3y+2z=1 3x+2y-z=4 x=2y-9z x+2y-3z=2 x-2y+6z=1