sin(a-π/4)=1/3 则cos(π/4+a)等于谢
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sin(a-π/4)=1/3则cos(π/4+a)等于谢sin(a-π/4)=1/3则cos(π/4+a)等于谢sin(a-π/4)=1/3则cos(π/4+a)等于谢cos(π/4+a)=sin(π
sin(a-π/4)=1/3 则cos(π/4+a)等于谢
sin(a-π/4)=1/3 则cos(π/4+a)等于
谢
sin(a-π/4)=1/3 则cos(π/4+a)等于谢
cos(π/4+a)=sin(π/2-(π/4+a))=sin(π/4-a)=-sin(a-π/4)=-1/3
因为sin(π/2-a)=cosa
cos(π/4+a)=sin(π/2-π/4-a)=-sin(a-π/4)=-1/3