设△ABC的内角A,B,C所对的边长分别为a,b,c,a=2根号3,tan((A+B)/2)+tan(c/2)=4,2sinBcosC=sinA,求A,B及b,c

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设△ABC的内角A,B,C所对的边长分别为a,b,c,a=2根号3,tan((A+B)/2)+tan(c/2)=4,2sinBcosC=sinA,求A,B及b,c设△ABC的内角A,B,C所对的边长分

设△ABC的内角A,B,C所对的边长分别为a,b,c,a=2根号3,tan((A+B)/2)+tan(c/2)=4,2sinBcosC=sinA,求A,B及b,c
设△ABC的内角A,B,C所对的边长分别为a,b,c,a=2根号3,tan((A+B)/2)+tan(c/2)=4,2sinBcosC=sinA,求A,B及b,c

设△ABC的内角A,B,C所对的边长分别为a,b,c,a=2根号3,tan((A+B)/2)+tan(c/2)=4,2sinBcosC=sinA,求A,B及b,c
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