(-1/3)^-2+(9/4)^(-1/2)+(1-根号2)^0-(-1/8)^(-1/3)
来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/20 04:29:16
(-1/3)^-2+(9/4)^(-1/2)+(1-根号2)^0-(-1/8)^(-1/3)(-1/3)^-2+(9/4)^(-1/2)+(1-根号2)^0-(-1/8)^(-1/3)(-1/3)^-
(-1/3)^-2+(9/4)^(-1/2)+(1-根号2)^0-(-1/8)^(-1/3)
(-1/3)^-2+(9/4)^(-1/2)+(1-根号2)^0-(-1/8)^(-1/3)
(-1/3)^-2+(9/4)^(-1/2)+(1-根号2)^0-(-1/8)^(-1/3)
原式
=9+2/3+1+2
=12又2/3
5/9+(3/4-1/2)
1,-1,3,-2,9-4()()找规律
数学化简(1-1/2*2)(1-1/3*3)(1-1/4*4).(1-1/9*9)(1-1/10*10)
(1-3/2*4)*(1-3/3*5)*...*(1-3/7*9)
2/9除以【(1/2+1/6)*3/4】
(1+2/1)(1+4/1)(1+6/1).(1+10/)(1-3/1)(1—5/1).(1-9/1)
(1-1/2)*(1-1/3)*(1-1/4)*……*(1-1/9) 算式
1,2,4,3,6,9,(),()
7/2+9/4+(-1/3)-0.25+(-1/6)
帮忙做一道简便运算1/1+(2/1-1/2)+(3/1-2/2+1/3)+(1/4-3/2+2/3-1/4)+...+(9/1-8/2+7/3-6/4+...+1/9)
计算:1/(1*3)+1/(3*5)+1/(5*7)+…+1/(49*51).因为1/(1*2)=1-(1/2),1/(2*3)=(1/2)*(1/3),1/(3*4)=(1/3)-(1/4),……,1/(9*10)=(1/9)-(1/10).所以1/(1*2)+1/(2*3)+1/(3*4)+…+1/(9
1+(-2)+3+(-4)+.+2003+(-2004)| 1-1/2 | + | 1/2-1/3 | + | 1/3-1/4 | +.+ | 1/9-1/10 |
(2-3)-(5*7-8)+11-(9-6-4)*(3+1)= (1/2-3)*(1-1/2-1/3)*(-1-1/2)*(-4)*(-2-1/3)-(-4)*(-1/8)*(2-1-1/3)*(2-1-1/3)*(2+1/3-1/2)=有负数和绝对值感激不尽
计算:(1)1+(-2)+3+(-4)+.+9+(-100) (2)1+(-2)+3+(-4)+5+(-6)+.+(2n-1)+(-2n)
1/(1×3)+1/(2×4)+1/(3×5)+……+1/(9×11)=?
3/4÷[(2/3-1/6)×9]
奥数简便运算:(1/1+(2/1-1/2)+(3/1-2/2+1/3)+(4/1-3/2+2/3-1/4)+.+(9/1-8/2+7/3-6/4+.+1/9
0.63+0.37÷ (2+3/2+1+9/4)