已知方程1/4+5（x-1/2009)=1/2,求式子3+20(x-1/2009)的值.如题.请列出过程.

已知方程1/4+5（x-1/2009)=1/2,求式子3+20(x-1/2009)的值.如题.请列出过程.
已知方程1/4+5（x-1/2009)=1/2,求式子3+20(x-1/2009)的值.
如题.请列出过程.

已知方程1/4+5（x-1/2009)=1/2,求式子3+20(x-1/2009)的值.如题.请列出过程.
设x-1/2009=A 则 1/4+5*A=1/2
A=1/20
所以3+20(x-1/2009)=3+20* 1/20 =3+1=4

4*[1/4+5（x-1/2009)]=1+20(x-1/2009)=2
3+20(x-1/2009)=2+2=4