求y=(x^2-3x+2)/(x^2+2x-3)的值域.

来源：学生作业帮助网编辑：六六作业网时间：2024/10/02 18:12:14

求y=(x^2-3x+2)/(x^2+2x-3)的值域.求y=(x^2-3x+2)/(x^2+2x-3)的值域.求y=(x^2-3x+2)/(x^2+2x-3)的值域.y=(x²－3x＋2)

求y=(x^2-3x+2)/(x^2+2x-3)的值域.
求y=(x^2-3x+2)/(x^2+2x-3)的值域.

求y=(x^2-3x+2)/(x^2+2x-3)的值域.
y=(x²－3x＋2)/(x²＋2x－3)
.=[(x－1)(x－2)]/[(x－1)(x＋3)]
.=(x－2)/(x＋3)
则值域是：{y|y≠1且y≠－1/4}

x^2+2x-3不等于0，可得（x+3）(x-1)不等于0，得x不等于1且x不等于-3

已知x-y/x+y=3,求代数式5(x-y)/x+y-x+y/2(x-y) 若2/x-1/y=3,求[y/x-y/x-y(x-y/x-x+y)]/x-2y/x的值已知|x|=2,|y|=3,|x+y|=-(x+y)求x-y (x-y)/(x+y)=3求( 3x-2y-1)/(x+y-5) y=3(x-y),x=2(x-y)求x,y的值已知x-y=3,求[（x+y)(x-y)-(x-y)^2+2y(x-y)]除以的值已知3x =2y 求x/x+y+y/x-y-y²/x²-y² y=(2x*x-2x+3)/(x*x-x+1),求值域? 求值域 1,y=(x+2)/(x*x+3x+6) 2,y=3x/(x*x+4) 已知2y-x=-3,求[4y(2x-y)-2x(2x-y)]/(2x-y x+y/2+ x-y/2=6 2(x+y)-3x+3y=24 求X Y {(x+y)/2+(x-y)/3=1,(x+y)-5(x-y)=2.求x=?,y=? 3X+2=X+20求X Y未知数 y=(X+1)(X+2)(X+3)求导数求函数y=(3x+4)/(x-2) (x 求y=(x^2)+2x(x≥0) y=-x+2x(x 已知x=3分之一,y=-2分之一,求代数式x-(x+y)+(x+2Y)-(x+3y)+(x+4y)...-(x+2009y) 已知x-3y=0,求(2x+y)/(x^2-2xy+y^2)X(x-y)