[10(6-x)+x]-[10x+(6-x)]=18 x=?

[10(6-x)+x]-[10x+(6-x)]=18 x=?
[10(6-x)+x]-[10x+(6-x)]=18 x=?

[10(6-x)+x]-[10x+(6-x)]=18 x=?
[10(6-x)+x]-[10x+(6-x)]=18
60 -10x +x -10x -6 +x =18
54 - 20x + 2x =18
18x=36
x=2

60-10x+x-10x-6+x=18
54-18=18x
x=2

cuole

先算括号里面的[60-10x+x]-[10x+6-x]=18x
[60-9x]-[9x+6]=18x
60-9x-9x-6=18x
...

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先算括号里面的[60-10x+x]-[10x+6-x]=18x
[60-9x]-[9x+6]=18x
60-9x-9x-6=18x
54-18x=18x
54=36x
x=3/2
x=1.5

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