y=(3x^5-4x^3)(4x^5+3x^3)求导
来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/18 13:39:06
y=(3x^5-4x^3)(4x^5+3x^3)求导y=(3x^5-4x^3)(4x^5+3x^3)求导y=(3x^5-4x^3)(4x^5+3x^3)求导先把括号打开得到Y=12x^10-7x^8-
y=(3x^5-4x^3)(4x^5+3x^3)求导
y=(3x^5-4x^3)(4x^5+3x^3)求导
y=(3x^5-4x^3)(4x^5+3x^3)求导
先把括号打开
得到Y=12x^10-7x^8-12x^6
再求导得y′=120x^9-56x^7-72x^5
分啊!
(5x+3y)(3y-5x)-(4x-y)(4y+x)=
4(x-y)-3(x-y)=9 5(x-y)+2(x-y)=11
3(x+y)-4(x-y)=11,2(x-y)+5(x+y)=27
3(x+y)+2(x-y)=36 4(x+y)-5(x-y)=2
先化简再求值(x-y)(x-2y)+(x-2y)(x-3y)-2(x-3y)(x-4y) x=4 y=5
若2x-3y+4=0则x(x*x-1)+x(5-x*x)-6y+7
因式分解(x-2y)(x-3y)+(x-4y)(x-5y)+(x-3y)(x-5y)+(x-2y)(x-4y)
3X=5Y (X+Y)*3X=(2Y+X)*4+2*2
分解因式 x(x-y)^5+xy(y-x)^4-x^3(x-y)3
用递归法求y=x-(x*x*x/3!)+(x*x*x*x*x/5!)-(x*x*x*x*x*x*x/7!)+.
化简[(3x+4y)^2-(2x+y)(2x-y)+(-x+y)(5x-y)]除以-2y,其中x=-1,y=1
(x+y-5)*(x+y-5)+(x-y+3)=0 x*x-y*y
已知:3x-5y=0,求x/y,x-y/y,x-y/x
xy²/(x²y-y) × x²/(x²+x)=(x²-3x)/(x²-5x) × 2x-10/(x²-6x+9)=化简求植x²-1/(x²-x-2)除以x/2x-4,其中x=1/2[x-x/(x+1)]除以[x/(2x-4)] ,其中x=√2+1
高数求极限 y=[(3^x +4^x +5^x)/3]^(1/x) (x->0)
(5x-3y)(3y+5x)-(4y-3x)(3x-4y)
5/4(x+y)(-x-y)^3*[-4/3(x-y)]*[-3/5(y-x)^2]
5x^3y(x-y)^3-10x^4y^3(y-x)^2因式分解